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JEE Main 2020 Physics, Capacitance — question figure A parallel plate capacitor has plates of area A separated by distance d between them. It is…

JEE Main 2020 — Physics Electromagnetism

2020mcqhard

JEE Main 2020 Physics, Capacitance — question figure

A parallel plate capacitor has plates of area A separated by distance ddd between them. It is filled with a dielectric which has a dielectric constant that varies as K(x)=K0(1+αx)K(x)={K}_{0}(1+\alpha x)K(x)=K0​(1+αx) where xxx is the distance measured from one of the plates. If (αd)<<1,(\alpha d)<<1,(αd)<<1, the total capacitance of the system is best given by the expression:

Official previous-year question

Held on 7 Jan 2020 · Verified 6 Jul 2026.

Options

  1. A

    AK0ϵ0d(1+αd2)\frac{A{K}_{0}{\epsilon }_{0}}{d}(1+\frac{\alpha d}{2})dAK0​ϵ0​​(1+2αd​)

  2. B

    AK0ϵ0d[1+(αd2)2]\frac{A{K}_{0}{\epsilon }_{0}}{d}[1+{(\frac{\alpha d}{2})}^{2}]dAK0​ϵ0​​[1+(2αd​)2]

  3. C

    AK0ϵ0d(1+α2d22)\frac{A{K}_{0}{\epsilon }_{0}}{d}(1+\frac{{\alpha }^{2}{d}^{2}}{2})dAK0​ϵ0​​(1+2α2d2​)

  4. D

    AK0ϵ0d(1+αd)\frac{A{K}_{0}{\epsilon }_{0}}{d}(1+\alpha d)dAK0​ϵ0​​(1+αd)

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