B0E0=C (speed of light in vacuum)
E0=B0C=3×10−8×3×108
=9CN
So,
E=9sin(ωt+kx+ϕ)
E=(9sin(1.6×103x+48×1010t)k^mV)
JEE Main 2020 — Physics Electromagnetism
If the magnetic field in a plane electromagnetic wave is given by B=3×10−8sin(1.6×103x+48×1010t)j^T, then what will be expression for electric field ?
Held on 7 Jan 2020 · Verified 6 Jul 2026.
E=(60sin(1.6×103x+48×1010t)k^mV)
E=(9sin(1.6×103x+48×1010t)k^mV)
E=(3×10−8sin(1.6×103x+48×1010t)j^mV)
E=(3×10−8sin(1.6×103x+48×1010t)i^mV)
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