
10+R10R×12=15×4
On solving
R=10Ω
JEE Main 2020 — Physics Electromagnetism
Four resistances of 15Ω,12Ω,4Ω and 10Ω respectively in cyclic order to form Wheatstone’s network. The resistance that is to be connected in parallel with the resistance of 10Ω to balance the network is ______________ Ω.
Held on 8 Jan 2020 · Verified 6 Jul 2026.
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