E0=B0×C=1.2×10−7×3×108=36
As the light is propagating in x direction.
& (E^×B^)∣∣C^
∴ E should be in j^ direction.
So electric field E=E0sinE⋅(x,t)=[−36sin(0.5×103x+1.5×1011t)j^]mV
For a plane electromagnetic wave, the magnetic field at a point x and time t is :
B(x,t)=[1.2×10−7sin(0.5×103x+1.5×1011t)k^]T.
The instantaneous electric field E corresponding to B is :
Held on 6 Sept 2020 · Verified 6 Jul 2026.
E(x,t)=[−36sin(0.5×103x+1.5×1011t)j^]mV
E(x,t)=[36sin(1×103x+0.5×1011t)j^]mV
E(x,t)=[36sin(0.5×103x+1.5×1011t)k^]mV
E(x,t)=[36sin(1×103x+15×1011t)i^]mV
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