As current in A and B are opposite in direction, net force on C can never be zero if it is kept between
A and B .

∴2πxμ0I1I=2π(x±d)μ0II2
I1(x±d)=I2x
(I2−I1)x=±I1d
x=±I2−I1I1d
JEE Main 2019 — Physics Electromagnetism
Two wires A & B are carrying currents I1 and I2 as shown in the figure. The separation between them is d . A third wire C carrying a current I is to be kept parallel to them at a distance x from A such that the net force acting on it is zero. The possible values of x are:

Held on 10 Apr 2019 · Verified 6 Jul 2026.
x=±(I1−I2)I1d
x=(I1+I2I1)d and x=(I1−I2)I2d
x=(I1+I2I2)d and x=(I1−I2I2)d
x=(I1−I2I1)d and x=(I1+I2)I2d
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