E=E0cos(ωt−K⋅r)
∴ At any time t,
K=6i^+8k^
B0=cE0=c10
λ=k2π=102π=5π
Also, E×B=c
∴ω=2πf=λ2πc
∣i^0Bxj^1Byk^0Bz∣=106i^+8k^
ω=(5π)2π×c=10c
∴i^[Bz−0]+j^(0)+k^(−Bx)=0.6i^−0.8k^
Comparing the coefficients on both sides,
∴Bz=0.6;Bx=−0.8
∣B0∣=c10(−0.8i^+0.6k^)=c−8i^+6k^
So the magnetic field,B=c1(−8i^+6k^)cos(6x+8z−10ct)tesla