Given, E1=1 V,E2=2 V,E3=3 V,r1=1Ω r2=1Ω and r3=1Ω VAB=VCD=r11+r21+r31r1E1+r2E2+r3E3=11+11+11+131=36=2 V
In the circuit shown, the potential difference between A and B is JEE Main 2019 Physics, Current Electricity — question figure
JEE Main 2019 — Physics Electromagnetism
In the circuit shown, the potential difference between A and B is 
Held on 11 Jan 2019 · Verified 6 Jul 2026.
Options
- A
1 V
- B
2 V
- C
3V
- D
6 V
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