Q=CV
The slope of graph will give the equivalent capacitance of the combination.
From graph A: C1+C2=10500=50 …(i)
From graph B: C1+C2C1C2=1080=8 …(ii)
From equation (i) & (ii)
C1C2=400 …(iii)
C1+C1400=50 ⇒C12−50C1+400=0
C1=250±2500−1600=250±30
=10μF,40μF