Given,
Current, i=1.5A,
Cross-section of the wire, A=5×10−6m2 and
Electron density, n=9×1028m−3.
As current, i=neAvd
⇒1.5=9×1028×1.6×10−19×5×10−6×vd
⇒vd=0.02mms−1.
JEE Main 2019 — Physics Electromagnetism
Drift speed of electrons, when 1.5A current flows in a copper wire of cross section 5mm2 is vd. If the electron density in copper is 9×1028m−3 the value of vd in mms−1 is close to (Take charge of an electron to be =1.6×10−19C)
Held on 9 Jan 2019 · Verified 6 Jul 2026.
0.2
3
2
0.02
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