Given that the galvanometer has 25 divisions and the current required for deflection one division is 4×10−4A
current for full scale deflection I=4×10−4×25A
=10−2A
To use this galvanometer as a voltmeter for a maximum voltage of 2.5V, we need to add a resistance R in series to the resistance of the galvanometer of G=50Ω such that,
I=R+G2.5⇒R=10−22.5−50=200ohm