In a voltmeter V∝l V=kl Now, it is given E=1.1 volt for l1=440 cm and V=0.5 volt for l2=220 cm Let the error in reading of voltmeter be ΔV then, 1.1=400 K and (0.5−ΔV)=220 K.⇒4401.1=2200.5−ΔV∴ΔV=−0.05 volt
In the experiment of calibration of voltmeter, a standard cell of e.m.f. 1.1 volt is balanced against 440 cm of potential wire. The potential difference across the ends of resistance is found to balance against 220 cm of the wire. The corresponding reading of voltmeter is 0.5 volt. The error in the reading of volmeter will be:
Held on 12 Apr 2014 · Verified 6 Jul 2026.
−0.15 volt
0.15 volt
0.5 volt
−0.05 volt
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