JEE Main 2026 — Chemistry Organic Chemistry

2026mcqmedium

The correct order of reactivity of $\mathrm{CH}_{3} \mathrm{Br}$ in methanol with the following nucleophiles is $\mathrm{F}^{-}, \mathrm{I}^{-}, \mathrm{C}_{2} \mathrm{H}_{5} \mathrm{O}^{-}$ and $\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{O}^{-}$

Official previous-year question

Held on 22 Jan 2026 · Verified 6 Jul 2026.

Options

A
$\mathrm{I}^{-}>\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{O}^{-}>\mathrm{F}^{-}>\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{O}^{-}$
B
$\mathrm{I}^{-}>\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{O}^{-}>\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{O}^{-}>\mathrm{F}^{-}$
C
$\mathrm{I}^{-}>\mathrm{F}^{-}>\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{O}^{-}>\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{O}^{-}$
D
$\mathrm{I}^{-}>\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{O}^{-}>\mathrm{F}^{-}>\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{O}^{-}$

Did you get this right?

Solution

In methanol (protic solvent), nucleophilicity is determined by basicity and solvation effects. Smaller ions are heavily solvated by the protic solvent, reducing their effective nucleophilicity.

C₂H₅O⁻ (ethoxide) is the strongest nucleophile as it is less solvated and highly basic.

C₆H₅O⁻ (phenoxide) is weaker due to resonance stabilization by the benzene ring.

F⁻ is highly solvated despite high basicity, reducing its nucleophilicity significantly.

I⁻ is the best nucleophile because it is the largest ion and least solvated in methanol.

The correct order is I⁻ > C₂H₅O⁻ > C₆H₅O⁻ > F⁻.

Your note

JEE Main Organic Chemistry in other years

Organic Chemistry 2025 Organic Chemistry 2024 Organic Chemistry 2023 Organic Chemistry 2022 Organic Chemistry 2021 Organic Chemistry 2020 Organic Chemistry 2019 Organic Chemistry 2018 Organic Chemistry 2017 Organic Chemistry 2016 Organic Chemistry 2015 Organic Chemistry 2014

More JEE Main Organic Chemistry questions

Consider the following reaction sequence ![JEE Main 2026 Chemistry, Alcohols Phenols and Ethers — question figure](https://prepforbharat.s3.ap-south-1.amazonaws.com/exam/615f0e999476412f48314daf/Chemistry/images/Alcohols_Phenols_and_Ethers/6983c1ad8bfdbb24356397bb/question_1__q_6983c1ad8bfdbb24356397bb__cdn-question-pool.getmarks.app__28S1_q_52_1_v2__2fe787b06d_final_ppt_sync.png) Compound $(\mathrm{y})$ develops characteristic colour with neutral $\mathrm{FeCl}_{3}$ solution. Identify the INCORRECT statement from the following for the above sequence.

2026medium

Given below are two statements: Statement I: Benzene is nitrated to give nitrobenzene, which on further treatment with $\mathrm{CH}_{3} \mathrm{COCl} / \mathrm{AlCl}_{3}$ will give ![JEE Main 2026 Chemistry, Hydrocarbons — question figure](https://prepforbharat.s3.ap-south-1.amazonaws.com/exam/615f0e999476412f48314daf/Chemistry/images/Hydrocarbons/6983c1898bfdbb24356395fc/question_1__q_6983c1898bfdbb24356395fc__cdn-question-pool.getmarks.app__22S1_q_54_1__65f8139d89_final_ppt_sync.png) Statement II: $-\mathrm{NO}_{2}$ group is a $m$-directing, and deactivating group. In the light of the above statements, choose the most appropriate answer from the options given below

2026medium

Given below are two statements: Statement I: $\left(\mathrm{CH}_{3}\right)_{3} \stackrel{\oplus}{\mathrm{C}}$ is more stable than $\stackrel{\oplus}{\mathrm{C}} \mathrm{H}_{3}$ as nine hyperconjugation interactions are possible in $\left(\mathrm{CH}_{3}\right)_{3} \stackrel{\oplus}{\mathrm{C}}$. Statement II: $\stackrel{\oplus}{\mathrm{C}} \mathrm{H}_{3}$ is less stable than $\left(\mathrm{CH}_{3}\right)_{3} \stackrel{\oplus}{\mathrm{C}}$ as only three hyperconjugation interactions are possible in $\stackrel{\oplus}{\mathrm{C}} \mathrm{H}_{3}$. In the light of the above statements, choose the correct answer from the options given below

2026medium

Which of the following reactions is an example of Wurtz reaction?

2026easy

A hydroxy compound $(\mathrm{X})$ with molar mass $122 \mathrm{~g} \mathrm{~mol}^{-1}$ is acetylated with acetic anhydride, using a large excess of the reagent ensuring complete acetylation of all hydroxyl groups. The product obtained has a molar mass of $290 \mathrm{~g} \mathrm{~mol}^{-1}$. The number of hydroxyl groups present in compound (X) is:

2026medium

View all Organic Chemistry questions

Keep practicing Organic Chemistry

Work through every JEE Main Organic Chemistry PYQ, year by year.

Browse all Chemistry topics

Options

$\mathrm{I}^{-}>\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{O}^{-}>\mathrm{F}^{-}>\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{O}^{-}$

$\mathrm{I}^{-}>\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{O}^{-}>\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{O}^{-}>\mathrm{F}^{-}$

$\mathrm{I}^{-}>\mathrm{F}^{-}>\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{O}^{-}>\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{O}^{-}$

$\mathrm{I}^{-}>\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{O}^{-}>\mathrm{F}^{-}>\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{O}^{-}$

Solution

In methanol (protic solvent), nucleophilicity is determined by basicity and solvation effects. Smaller ions are heavily solvated by the protic solvent, reducing their effective nucleophilicity.

C₂H₅O⁻ (ethoxide) is the strongest nucleophile as it is less solvated and highly basic.

C₆H₅O⁻ (phenoxide) is weaker due to resonance stabilization by the benzene ring.

F⁻ is highly solvated despite high basicity, reducing its nucleophilicity significantly.

I⁻ is the best nucleophile because it is the largest ion and least solvated in methanol.

The correct order is I⁻ > C₂H₅O⁻ > C₆H₅O⁻ > F⁻.

JEE Main 2026 — Chemistry Organic Chemistry

Options

Did you get this right?

Solution

Your note

JEE Main Organic Chemistry in other years

More JEE Main Organic Chemistry questions

Other Chemistry topics for JEE Main

Physical Chemistry

Inorganic Chemistry

Keep practicing Organic Chemistry

JEE Main 2026 — Chemistry Organic Chemistry

Options

Did you get this right?

Solution

Your note

JEE Main Organic Chemistry in other years

More JEE Main Organic Chemistry questions

Other Chemistry topics for JEE Main

Physical Chemistry

Inorganic Chemistry

Keep practicing Organic Chemistry