The large difference in the melting and boiling points of oxygen and sulphur is due to atomicity as oxygen exists as O2 and sulphur exists as S8.
The large difference between the melting and boiling points of oxygen and sulphur may be explained on the basis of
Held on 24 Jan 2025 · Verified 6 Jul 2026.
Atomicity
Electron gain enthalpy
Electronegativity
Atomic size
Sign in to track your attempts and accuracy.
Sign in to keep a private note on this question. Nothing you write is ever public.
By usual analysis, 1.00 g of compound $(\mathrm{X})$ gave 1.79 g of magnesium pyrophosphate. The percentage of phosphorus in compound $(X)$ is : (nearest integer) (Given, molar mass in $\mathrm{g} \mathrm{mol}^{-1}: \mathrm{O}=16, \mathrm{Mg}=24, \mathrm{P}=31$)
Among $Fe^{2+}, Fe^{3+}, Cr^{2+}$ and $Zn^{2+}$, the ion that shows positive borax bead test and with highest ionisation enthalpy is:
Consider three metal chlorides $\mathrm{x}, \mathrm{y}$ and z, where x is water soluble at room temperature, y is sparingly soluble in water at room temperature and z is soluble in hot water. $\mathrm{x}, \mathrm{y}$ and z are respectively
Among $Fe^{3+}$, $Pb^{2+}$, $Cu^{2+}$ and $Mn^{2+}$, identify the one that gets precipitated out while passing $H_2S$ in presence of $NH_4OH$ as group reagent. The highest possible oxidation state of the corresponding metal is
Which of the following sequences of hybridisation, geometry and magnetic nature are correct for the given coordination compounds ? A. $[\text{NiCl}_4]^{2-}$ $-$ sp$^3$, tetrahedral, paramagnetic B. $[\text{Ni(NH}_3)_6]^{2+}$ $-$ sp$^3$d$^2$, octahedral, paramagnetic C. $[\text{Ni(CO)}_4]$ $-$ sp$^3$, tetrahedral, paramagnetic D. $[\text{Ni(CN)}_4]^{2-}$ $-$ dsp$^2$, square planar, diamagnetic Choose the correct answer from the options given below :
Work through every JEE Main Inorganic Chemistry PYQ, year by year.