(i) The oxidation state of Mn in oxide (Mn2O7) is:
Let us consider Mn as x.
⇒2x+7(−2)=0
⇒2x+(−14)=0
⇒2x−14=0
⇒2x=14
⇒x=7
(ii) The oxidation state of Ruthenium in oxide (RuO4) is:
Consider Ru as x.
⇒x+4(−2)=0
⇒x−8=0
⇒x=8
The oxidation state of Osmium in oxide (OsO4) is:
Consider Os as x.
⇒x+4(−2)=0
⇒x−8=0
⇒x=8
Hence, Ruthenium and Osmium has +7 oxidation state in its oxide.
(iii) Sc has ns2(n−1)d1 electronic configuration.
It utilizes two electrons from its ns sub-shell then its oxidation state = +2. When it utilizes both the electrons then its oxidation state = +3.
(iv) In the modern periodic table, chromium metal is present in group 6. It is a transition metal and belongs to the first transition series. The atomic number of chromium is 24. Its electronic configuration is [Ar]3d54s1.
It has five electrons in the 3d sub-shell and one electron in the 4s sub-shell. Thus, chromium metal has six valence electrons. Chromium can lose some or all of its valence electrons to form ions with different oxidation states. Thus, chromium shows the oxidation states of +1, +2, +3, +4, +5, and +6 respectively.
The most common oxidation states of chromium are +2, +3, and +6.
So, the statement (i), (ii) and (iv) are correct.