Match List-I with List-II LIST-I Coordination Complex LIST-II Number of unpaired electrons A. ${[\mathrm{Cr}(\mathrm{CN}{)}_{6}]}^{3-}$ I. 0 B. ${[\mathrm{Fe}{({H}_{2}O)}_{6}]}^{2+}$ II. 3 C. ${[\mathrm{Co}{({\mathrm{NH}}_{3})}_{6}]}^{3+}$ III. 2 D. ${[\mathrm{Ni}{({\mathrm{NH}}_{3})}_{6}]}^{2+}$ IV. 4 Choose the correct answer from the options given below:

${[\mathrm{Cr}(\mathrm{CN}{)}_{6}]}^{3-}$ ion, oxidation state of $\mathrm{Cr}$ is +3 and its valence shell electronic configuration is $3{d}^{3}$. There are $3$ unpaired electrons in $3d$ orbital. (A). ${[\mathrm{Cr}(\mathrm{CN}{)}_{6}]}^{3-}$ ![JEE Main 2023 Chemistry, Coordination Compounds — solution figure 1](https://prepforbharat.s3.ap-south-1.amazonaws.com/exam/615f0e999476412f48314daf/Chemistry/images/Coordination_Compounds/648b5a70417cc3fb48d6845a/solution_1__q_648b5a70417cc3fb48d6845a__cdn-question-pool.getmarks.app__44c58776-a70a-4244-ba5b-a03663fc661c-image__4832c052c7_final_ppt_sync.png) No. of unpaired electrons $=3$ ${[\mathrm{Fe}{({H}_{2}O)}_{6}]}^{2+}$ ion, oxidation state of $\mathrm{Fe}$ is +2 and its valence shell electronic configuration is $3{d}^{6}$. There are 4 unpaired electrons in 3d orbital. So, you can say the hybridisation here would be ${\mathrm{sp}}^{3}{d}^{2}$. (B). ${[\mathrm{Fe}{({H}_{2}O)}_{6}]}^{2+}$ ![JEE Main 2023 Chemistry, Coordination Compounds — solution figure 2](https://prepforbharat.s3.ap-south-1.amazonaws.com/exam/615f0e999476412f48314daf/Chemistry/images/Coordination_Compounds/648b5a70417cc3fb48d6845a/solution_2__q_648b5a70417cc3fb48d6845a__cdn-question-pool.getmarks.app__3798fd3e-1185-4aee-b76e-b1b77508fc07-image__44631052c6_final_ppt_sync.png) No. of unpaired electrons $=4$ ${[\mathrm{Co}{({\mathrm{NH}}_{3})}_{6}]}^{3+}$ in this oxidation state of central metal atom is $+3$ and it has no unpaired electrons. (C). ${[\mathrm{Co}{({\mathrm{NH}}_{3})}_{6}]}^{3+}$ ![JEE Main 2023 Chemistry, Coordination Compounds — solution figure 3](https://prepforbharat.s3.ap-south-1.amazonaws.com/exam/615f0e999476412f48314daf/Chemistry/images/Coordination_Compounds/648b5a70417cc3fb48d6845a/solution_3__q_648b5a70417cc3fb48d6845a__cdn-question-pool.getmarks.app__451c225e-ce19-4c6a-a5be-0afdf03c0661-image__e1dfcff9f7_final_ppt_sync.png) No. of unpaired electrons $=0$ ${[\mathrm{Ni}{({\mathrm{NH}}_{3})}_{6}]}^{2+}$ the oxidation state of $\mathrm{Ni}$ is ${\mathrm{Ni}}^{2+}$ and it has two unpaired electrons. (D) ${[\mathrm{Ni}{({\mathrm{NH}}_{3})}_{6}]}^{2+}$ ![JEE Main 2023 Chemistry, Coordination Compounds — solution figure 4](https://prepforbharat.s3.ap-south-1.amazonaws.com/exam/615f0e999476412f48314daf/Chemistry/images/Coordination_Compounds/648b5a70417cc3fb48d6845a/solution_4__q_648b5a70417cc3fb48d6845a__cdn-question-pool.getmarks.app__fb7bc073-c73b-439a-8763-a6ca4ea0d2a2-image__1b028c23b8_final_ppt_sync.png) No. of unpaired electrons $=2$ So the correct option among the given is $A$.

JEE Main 2023 — Chemistry Inorganic Chemistry

2023mcqmedium

Match List-I with List-II

	LIST-I Coordination Complex		LIST-II Number of unpaired electrons
A.	${[\mathrm{Cr}(\mathrm{CN}{)}_{6}]}^{3-}$	I.	0
B.	${[\mathrm{Fe}{({H}_{2}O)}_{6}]}^{2+}$	II.	3
C.	${[\mathrm{Co}{({\mathrm{NH}}_{3})}_{6}]}^{3+}$	III.	2
D.	${[\mathrm{Ni}{({\mathrm{NH}}_{3})}_{6}]}^{2+}$	IV.	4

Choose the correct answer from the options given below:

Official previous-year question

Held on 8 Apr 2023 · Verified 6 Jul 2026.

Options

A
A-II, B-IV, C-I, D-III
B
A-III, B-IV, C-I, D-II
C
A-II, B-I, C-IV, D-III
D
A-IV, B-III, C-II, D-I

Did you get this right?

Solution

${[\mathrm{Cr}(\mathrm{CN}{)}_{6}]}^{3-}$ ion, oxidation state of $\mathrm{Cr}$ is +3 and its valence shell electronic configuration is $3{d}^{3}$ . There are $3$ unpaired electrons in $3d$ orbital.

(A). ${[\mathrm{Cr}(\mathrm{CN}{)}_{6}]}^{3-}$

JEE Main 2023 Chemistry, Coordination Compounds — solution figure 1

No. of unpaired electrons $=3$

${[\mathrm{Fe}{({H}_{2}O)}_{6}]}^{2+}$ ion, oxidation state of $\mathrm{Fe}$ is +2 and its valence shell electronic configuration is $3{d}^{6}$ . There are 4 unpaired electrons in 3d orbital. So, you can say the hybridisation here would be ${\mathrm{sp}}^{3}{d}^{2}$ .

(B). ${[\mathrm{Fe}{({H}_{2}O)}_{6}]}^{2+}$

JEE Main 2023 Chemistry, Coordination Compounds — solution figure 2

No. of unpaired electrons $=4$

${[\mathrm{Co}{({\mathrm{NH}}_{3})}_{6}]}^{3+}$ in this oxidation state of central metal atom is $+3$ and it has no unpaired electrons.

(C). ${[\mathrm{Co}{({\mathrm{NH}}_{3})}_{6}]}^{3+}$

JEE Main 2023 Chemistry, Coordination Compounds — solution figure 3

No. of unpaired electrons $=0$

${[\mathrm{Ni}{({\mathrm{NH}}_{3})}_{6}]}^{2+}$ the oxidation state of $\mathrm{Ni}$ is ${\mathrm{Ni}}^{2+}$ and it has two unpaired electrons.

(D) ${[\mathrm{Ni}{({\mathrm{NH}}_{3})}_{6}]}^{2+}$

JEE Main 2023 Chemistry, Coordination Compounds — solution figure 4

No. of unpaired electrons $=2$

So the correct option among the given is $A$ .

Your note

JEE Main Inorganic Chemistry in other years

Inorganic Chemistry 2026 Inorganic Chemistry 2025 Inorganic Chemistry 2024 Inorganic Chemistry 2022 Inorganic Chemistry 2021 Inorganic Chemistry 2020 Inorganic Chemistry 2019 Inorganic Chemistry 2018 Inorganic Chemistry 2017 Inorganic Chemistry 2016 Inorganic Chemistry 2015 Inorganic Chemistry 2014

Keep practicing Inorganic Chemistry

Work through every JEE Main Inorganic Chemistry PYQ, year by year.

Browse all Chemistry topics

Solution

${[\mathrm{Cr}(\mathrm{CN}{)}_{6}]}^{3-}$ ion, oxidation state of $\mathrm{Cr}$ is +3 and its valence shell electronic configuration is $3{d}^{3}$ . There are $3$ unpaired electrons in $3d$ orbital.

(A). ${[\mathrm{Cr}(\mathrm{CN}{)}_{6}]}^{3-}$

JEE Main 2023 Chemistry, Coordination Compounds — solution figure 1

No. of unpaired electrons $=3$

(B). ${[\mathrm{Fe}{({H}_{2}O)}_{6}]}^{2+}$

JEE Main 2023 Chemistry, Coordination Compounds — solution figure 2

No. of unpaired electrons $=4$

${[\mathrm{Co}{({\mathrm{NH}}_{3})}_{6}]}^{3+}$ in this oxidation state of central metal atom is $+3$ and it has no unpaired electrons.

(C). ${[\mathrm{Co}{({\mathrm{NH}}_{3})}_{6}]}^{3+}$

JEE Main 2023 Chemistry, Coordination Compounds — solution figure 3

No. of unpaired electrons $=0$

${[\mathrm{Ni}{({\mathrm{NH}}_{3})}_{6}]}^{2+}$ the oxidation state of $\mathrm{Ni}$ is ${\mathrm{Ni}}^{2+}$ and it has two unpaired electrons.

(D) ${[\mathrm{Ni}{({\mathrm{NH}}_{3})}_{6}]}^{2+}$

JEE Main 2023 Chemistry, Coordination Compounds — solution figure 4

No. of unpaired electrons $=2$

So the correct option among the given is $A$ .

JEE Main 2023 — Chemistry Inorganic Chemistry

Options

Did you get this right?

Solution

Your note

JEE Main Inorganic Chemistry in other years

More JEE Main Inorganic Chemistry questions

Other Chemistry topics for JEE Main

Physical Chemistry

Organic Chemistry

Keep practicing Inorganic Chemistry

JEE Main 2023 — Chemistry Inorganic Chemistry

Options

Did you get this right?

Solution

Your note

JEE Main Inorganic Chemistry in other years

More JEE Main Inorganic Chemistry questions

Other Chemistry topics for JEE Main

Physical Chemistry

Organic Chemistry

Keep practicing Inorganic Chemistry