⇒2n(n−1)=6n=4 For maximum wavelength energy difference between states should be minimum because λ=ΔEhc So, transition state in n=4 to n=3
NEET UG 2009 — Physics Modern Physics
The ionization energy of the electron in the hydrogen atom in its grounds state is 13.6eV. The atoms are excited to higher energy levels to emit radiations of 6 wavelengths. Maximum wavelength of emitted radiation corresponds to the transition between :
Held on 30 Apr 2009 · Verified 9 Jul 2026.
n=4 to n=3 states
n=3 to n=2 states
n=3 to n=1 states
n=2 to n=1 states
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