Key Idea Number of spectral lines abtained due to transition of electron from nth orbit to lower orbit is N=2n(n−1) and for maximum wavelength the difference between the orbits of the series should be minimum. Number of spectral lines N=2n(n−1) ⇒ or or or 2n(n−1)n2−n−12(n−4)(n+3)n=6=0=0=4 Now as the first line of the series has the maximum wavelength, therefore electron jumps from the 4th orbit to the third orbit.
The ionization energy of the electron in the hydrogen atom in its ground state is 13.6 eV. The atoms are excited to higher energy levels to emit…
NEET UG 2009 — Physics Modern Physics
2009mcqeasy
The ionization energy of the electron in the hydrogen atom in its ground state is 13.6eV. The atoms are excited to higher energy levels to emit radiations of 6 wavelengths. Maximum wavelength of emitted radiation corresponds to the transition between
Official previous-year question
Held on 30 Apr 2009 · Verified 9 Jul 2026.
Options
- A
n=3 to n=2 states
- B
n=3 to n=1 states
- C
n=2 to n=1 states
- D
n=4 to n=3 states
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