Binding energy of a nucleus containing N neutrons and Z protons is ⇒⇒⇒BE=[NMn+ZMp−M(A,Z)]c2c2BE=NMn+ZMp−M(A,Z)c2BE=(A−Z)Mn+ZMp−M(A,Z)M(A,Z)=ZMp+(A−Z)Mn−BE/c2
If M(A, Z), M_P and M_n denote the masses of the nucleus _Z^A X, proton and neutron respectively in units of u (1 u=931.5 MeV / c^2 ) and BE…
NEET UG 2008 — Physics Modern Physics
2008mcqhard
If M(A,Z),MP and Mn denote the masses of the nucleus ZAX, proton and neutron respectively in units of u(1u=931.5MeV/c2) and BE represents its binding energy in MeV, then
Official previous-year question
Held on 30 Apr 2008 · Verified 9 Jul 2026.
Options
- A
M(A,Z)=ZMp+(A−Z)Mn−BE/c2
- B
M(A,Z)=ZMp+(A−Z)Mn+BE
- C
M(A,Z)=ZMp+(A−Z)Mn−BE
- D
M(A,Z)=ZMpP+(A−Z)Mnn+BE/c2
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