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In the reaction _1^2 H+ _1^3 H → _2^4 He+ _0^1 n, if the binding energies of _1^2 H, _1^3 H and _2^4 He are respectively a, b and c (in Me V), then…

NEET UG 2005 — Physics Modern Physics

2005mcqeasy

In the reaction 12H+13H→24He+01n{ }_1^2 \mathrm{H}+{ }_1^3 \mathrm{H} \rightarrow{ }_2^4 \mathrm{He}+{ }_0^1 n12​H+13​H→24​He+01​n, if the binding energies of 12H,13H{ }_1^2 \mathrm{H},{ }_1^3 \mathrm{H}12​H,13​H and 24He{ }_2^4 \mathrm{He}24​He are respectively a,ba, ba,b and ccc (in Me V), then the energy (in MeV\mathrm{MeV}MeV ) released in this reaction is:

Official previous-year question

Held on 30 Apr 2005 · Verified 9 Jul 2026.

Options

  1. A

    a+b+ca+b+ca+b+c

  2. B

    a+b−ca+b-ca+b−c

  3. C

    c−a−bc-a-bc−a−b

  4. D

    c+a−bc+a-bc+a−b

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