Loss of energy, ΔE=21Itωi2−21(It+Ib)It2ωi2 =21(It+Ib)IbItωi2
A circular disk of moment of inertia It is rotating in a horizontal plane, about its symmetry axis, with a constant angular speed ωi. Another disk of moment of inertia Ib is dropped coaxially onto the rotating disk. Initially the second disk has zero angular speed. Eventually both the disks rotate with a constant angular speed ωf. The energy lost by the initially rotating disc due to friction is
Held on 30 Apr 2010 · Verified 9 Jul 2026.
21(It+Ib)Ib2ωi2
21(It+Ib)It2ωi2
21(It+Ib)Ib−Itωi2
21(Lt+Ib)IbItωi2
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