Frequency v=2πmeB KE=21mv2 and radius R=eBmv Here, velocity v=T/2πR=T2πR=2πRv ∴ Radius R=eBm(2πRv) Magnetic field B=e2πmv Kinetic energy K=21m(2πRv)2=2mπ2v2R2
NEET UG 2012 — Physics Electromagnetism
An alternating electric field of frequency v, is applied across the dees (radius =R) of a cyclotron that is being used to accelerate protons (mass =m ). The operating magnetic field (B) used in the cyclotron and the kinetic energy (K) of the proton beam, produced by it, are given by
Held on 30 Apr 2012 · Verified 9 Jul 2026.
B=emv and K=2mπ2v2R2
B=e2πmv and K=m2πvR2
B=e2πmv and K=2mπ2v2R2
B=emv and K=m2πvR2
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