The magnetic flux linked with the primary coil is given by ϕ=ϕ0+4t So, voltage across primary Vp=dtdϕ=dtd(ϕ0+4t)=4 volt (as ϕ0= constant ) Also, we have Np=50 and Ns=1500 From relation, VpVs=NpNsor Vs=VpNpNs=4(501500)=120 V
NEET UG 2007 — Physics Electromagnetism
The primary and secondary coils of a transformer have 50 and 1500 turns respectively. If the magnetic flux ϕ linked with the primary coil is given by ϕ=ϕv+4t, where ϕ is in webers, t is time in seconds and ϕv is a constant, the output voltage across the output voltage across the secondary coil is:
Held on 30 Apr 2007 · Verified 9 Jul 2026.
120 volts
220 volts
30 volts
90 volts.
Sign in to track your attempts and accuracy.
Sign in to keep a private note on this question. Nothing you write is ever public.
Two point charges +2μC and -2μC are placed 10 cm apart. The electric field at the midpoint is:
A parallel plate capacitor made of circular plates is being charged such that the surface charge density on its plates is increasing at a constant rate with time. The magnetic field arising due to displacement current is :
Two identical charged conducting spheres $A$ and $B$ have their centres separated by a certain distance. Charge on each sphere is q and the force of repulsion between them is $F$. A third identical uncharged conducting sphere is brought in contact with sphere A first and then with B and finally removed from both. New force of repulsion between spheres $A$ and $B$ (Radii of $A$ and $B$ are negligible compared to the distance of separation so that for calculating force between them they can be considered as point charges) is best given as :
The electric potential at distance r from a point charge q is V = q/(4πε₀r). The electric field E is:
The current passing through the battery in the given circuit, is : 
Work through every NEET UG Electromagnetism PYQ, year by year.