For a mirror with magnification m = -3 (real image), object and image distances satisfy |u| + |v| = 40 cm.
Since m = v/u = -3, we have v = -3u, giving u + 3u = 40, so u = 10 cm and v = -30 cm.
Using mirror formula: f1=u1+v1=101+−301=303−1=151
Hence f = -15 cm.