Let R1 and R2 be the radii of the front and back surfaces of the biconvex lens. The power of the biconvex lens is P1=(1.5−1)(R11+R21)=0.5(R11+R21).
The plano-concave lens has a flat surface and a concave surface of radius R2 (matching the back surface of the biconvex lens). Its power is P2=(1.7−1)(R21)=R20.7.
Since the magnitudes of power are equal: 0.5(R11+R21)=R20.7
Simplifying: R10.5+R20.5=R20.7, which gives R10.5=R20.2
Therefore: R2R1=0.20.5=25