For lens P:
v11−u11=f11
v11−−151=101
v11=101−151=301⇒v1=30 cm
Magnification m1=u1v1=−1530=−2
The image formed by lens P acts as a virtual object for lens Q. Since the distance between the lenses is 15 cm, the object distance for lens Q is:
u2=30−15=+15 cm
For lens Q:
v21−u21=f21
v21−151=151
v21=152⇒v2=7.5 cm
The positive sign indicates that the final image is real and formed 7.5 cm to the right of lens Q.
Magnification m2=u2v2=157.5=21
Total magnification m=m1×m2=−2×21=−1
Since ∣m∣=1, the size of the final image is the same as that of the object AB.
Answer: real, formed at 7.5 cm right of lens Q, with a size same as that of AB