For B $\begin{aligned}
& \frac{\mu_2}{\mathrm{V}}-\frac{\mu_1}{\mathrm{u}}=\frac{\mu_2-\mu_1}{\mathrm{R}} \
& \frac{1.5}{\mathrm{V}}+\frac{1}{\frac{R}{2}}=\frac{0.5}{-\mathrm{R}} \
& \frac{1.5}{\mathrm{V}}=-\frac{1}{2 \mathrm{R}}-\frac{2}{\mathrm{R}} \
& \frac{1.5}{\mathrm{V}}=\frac{-5}{2 \mathrm{R}} \Rightarrow V_B=-0.6 \mathrm{R}
\end{aligned}ForA\begin{aligned}
& \frac{1.5}{V}+\frac{2}{3 R}=\frac{0.5}{-R} \
& \frac{1.5}{V}=-\frac{1}{2 R}-\frac{2}{3 R} \
& \frac{1.5}{V}=-\frac{7}{6 R} \
& V_A=-\frac{9}{7} R
\end{aligned}Distancebetweenimages=2 \mathrm{R}-\left(0.6 \mathrm{R}+\frac{9}{7} \mathrm{R}\right)=0.114 \mathrm{R}$
JEE Main 2025 — Physics Optics
2025mcqhard
Two concave refracting surfaces of equal radii of curvature and refractive index 1.5 face each other in air as shown in figure. A point object O is placed midway, between P and B . The separation between the images of O, formed by each refracting surface is :
Official previous-year question
Held on 29 Jan 2025 · Verified 6 Jul 2026.
Options
- A
0.214 R
- B
0.411 R
- C
0.124 R
- D
0.114 R
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