
after passing through third poleriser, Intensity of both the waves must be 4I0 now, at a point where path diff is 3λ, phase difference $\begin{aligned}
& \Delta \phi=2 \mathrm{~K}\left(\frac{\Delta \mathrm{x}}{\lambda}\right)=\frac{2 \pi}{3} \
& \therefore \mathrm{I}_{\mathrm{res}}=\sqrt{\left(\frac{\mathrm{I}_0}{4}\right)^2+\left(\frac{\mathrm{I}_0}{4}\right)^2+2\left(\frac{\mathrm{I}_0}{4}\right)^2} \cos \frac{2 \pi}{3} \
& =\frac{\mathrm{I}_0}{4}
\end{aligned}$
