Equivalent focal length
$\begin{aligned}
& \frac{1}{f}=\frac{1}{f_1}+\frac{1}{f_2} \
& =\frac{1}{30}+\frac{1}{-20}=\frac{2-3}{60}=-\frac{1}{60} \
& f=-60 \mathrm{~cm}
\end{aligned}$
Lens formula
$\begin{aligned}
& \frac{1}{\mathrm{v}}-\frac{1}{\mathrm{u}}=\frac{1}{\mathrm{f}} \
& \frac{1}{\mathrm{v}}-\frac{1}{-20}=\frac{1}{-60} \
& \mathrm{v}=-15 \mathrm{~cm}
\end{aligned}$