
The position of first minima is
y=2×aλD(y is height of the point from the axis passing through the mid-point of A1andA2)
Since the first minima is in front of the slit as shown in the figure,
2×aλD=2a
⇒a=λD=800×10−9×5×10−2=2×10−4m=0.2mm
JEE Main 2023 — Physics Optics
In a Young’s double slit experiment, two slits are illuminated with a light of wavelength 800nm. The line joining A1P is perpendicular to A1A2 as shown in the figure. If the first minimum is detected at P, the value of slits separation a will be :

The distance of screen from slits D=5cm.
Held on 29 Jan 2023 · Verified 6 Jul 2026.
0.4mm
0.5mm
0.2mm
0.1mm
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