
Let angle BAC is θ.
Applying Snell's law at E, we get 1×sin60∘=34×sinθ
⇒sinθ=833⇒tanθ=1−(sinθ)2sinθ=3733
Now, BC=1.5×tanθ=1.28
Then, AB=2.15−BC=0.86m
Required value, DF=ABtan30∘=0.5015m≈50cm
JEE Main 2023 — Physics Optics
A pole is vertically submerged in swimming pool, such that it gives a length of shadow 2.15m within water when sunlight is incident at an angle of 30∘ with the surface of water. If swimming pool is filled to a height of 1.5m, then the height of the pole above the water surface in centimeters is ({n}_{w}=\frac{4}{3})________.
Held on 6 Apr 2023 · Verified 6 Jul 2026.
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