Let the fish be at a depth x from the surface and let the bird be at height y from the surface. So, with respect to fish
y′=μy+x⇒y′=34y+x
Differentiating with respect to time,
dtdy′=3dt4dy+dtdx
⇒34y+dtdx=−12
⇒34⋅dtdy=−12+8=−4
⇒dtdy=−3ms−1
JEE Main 2023 — Physics Optics
A fish rising vertically upward with a uniform velocity of 8ms–1, observes that a bird is diving vertically downward towards the fish with the velocity of 12ms–1. If the refractive index of water is 34, then the actual velocity of the diving bird to pick the fish, will be__________m{s}^{-1}.

Held on 13 Apr 2023 · Verified 6 Jul 2026.
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