The given data is
λ1=7000Ao
λ2=5500Ao
d=2.5×10−3m
D=1.5m
The path difference is given by
nλ1=mλ2
7n=5.5m
⇒14n=11m⇒n=11 and m=14
The formula for the distance of a bright fringe is
y=dnλ1D
⇒y=2.5×10−311×7×10−7×1.5
=46.2×10−4=462×10−5
It is given that
n×10−5=462×10−5⇒n=462