f=4DD2−d2=4(100)1002−402=4(100)(100+40)(100−40)=21cm
P=f1=21100=100N
N=476.19
JEE Main 2020 — Physics Optics
The distance between an object and a screen is 100cm. A lens can produce real image of the object on the screen for two different positions between the screen and the object. The distance between these two positions is 40cm. If the power of the lens is close to (100N)D where N is an integer, the value of N is _________
Held on 4 Sept 2020 · Verified 6 Jul 2026.
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