f1=(μ−1)(R11−R21)
R1=∞
R2=−30cm
f1=(1.5−1)(∞1−−301)
f1=300.5
f = 60cm
JEE Main 2020 — Physics Optics
A point object in air is in front of the curved surface of a plano-convex lens. The radius of curvature of the curved surface is 30cm and the refractive index of the lens material is 1.5, then the focal length of the lens (in cm) is ___________.
Held on 8 Jan 2020 · Verified 6 Jul 2026.
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