
Given,
Intensity of plane polarized light of large cross-sectional area is I0=3.3Wm−2
Area of cross-section of polarizer is A=3×10−4m2
Angular speed of rotation is ω=31.4rads−1
The intensity of light is the given by the definition,
I=ATE...(1)
Intensity of light passing through the polarizer as polarizer rotates is given by
Iavg=I0T1∫0Tcos2(ωt)dt
⇒Iavg=I0T1∫0T[21+cos(2ωt)]dt
⇒Iavg=I02T1[∫0Tdt+∫0Tcos(2ωt)dt]
⇒Iavg=I02T1[T+0]
⇒Iavg=2I0...(2)
Using equation (1) and (2) we get energy per revolution is given by
E=2I0AT=2I0Aω2π
E=23.3×3×10−431.43.14
E≃1×10−4J