
For reflected light not be completely polarized,
tanr=μwμg=μ1.5
For minimum μr is maximum. r is maximum when i is maximum i.e. i=90o
⇒sinr=μ1
⇒tanr=μ2−11
∴μ2−11=μ1.5
⇒μ2=2.25(μ2−1)
⇒1.25μ2=2.25
⇒μ=1.252.25
=59=53
JEE Main 2019 — Physics Optics
Consider a tank made of glass (refractive index 1.5 ) with a thick bottom. It is filled with a liquid of refractive index μ. A student finds that, irrespective of what the incident angle i (see figure) is for a beam of light entering the liquid, the light reflected from the liquid glass interface is never completely polarized. For this to happen, the minimum value of μ is:

Held on 9 Jan 2019 · Verified 6 Jul 2026.
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