a=0.1mm=10−4m
λ=6000×10−10=6×10−7m
D=0.5m
For 3rd dark
asinθ=3λ
sinθ=a3λ=Dx
x=a3λD
=10−43×6×10−7×0.5
=9mm
JEE Main 2017 — Physics Optics
A single slit of width 0.1mm is illuminated by a parallel beam of light of wavelength 6000Å and diffraction bands are observed on a screen 0.5m from the slit. The distance of the third dark band from the central bright band is:
Held on 9 Apr 2017 · Verified 6 Jul 2026.
9mm
3mm
4.5mm
1.5mm
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