For secondary minima dsinθ=nλ
sinθ=dnλ
For second minima
n=2
sinθ=d2λ=tanθ1=Dx1
For fourth minima n=4
sinθ2=d4λ=Dx2
Distance between both minima is x2−x1=d4λ−d2λ=d2λ=6−3=3cm
Width of central maxima,=d2λ=3cm
JEE Main 2017 — Physics Optics
A single slit of width b is illuminated by a coherent monochromatic light of wavelength λ. If the second and fourth minima in the diffraction pattern at a distance 1cm from the slit are at 3cm and 6cm respectively from the central maximum, what is the width of the central maximum? (i.e. distance between first minimum on either side of the central maximum)
Held on 8 Apr 2017 · Verified 6 Jul 2026.
4.5cm
1.5cm
6.0cm
3.0cm
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