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In a Young's double slit experiment with light of wavelength λ , the separation of slits is d and distance of screen is D such that Dgg dgg λ . If…

JEE Main 2015 — Physics Optics

2015mcqmedium

In a Young's double slit experiment with light of wavelength λ,\lambda ,λ, the separation of slits is ddd and distance of screen is DDD such that D≫d≫λD\gg d\gg \lambdaD≫d≫λ . If the Fringe width is β\betaβ , the distance from point of maximum intensity to the point where intensity falls to half of the maximum intensity on either side is:

Official previous-year question

Held on 11 Apr 2015 · Verified 6 Jul 2026.

Options

  1. A

    β4\frac{\beta }{4}4β​

  2. B

    β3\frac{\beta }{3}3β​

  3. C

    β6\frac{\beta }{6}6β​

  4. D

    β2\frac{\beta }{2}2β​

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