Given : f0=1.2 cm;fe=3.0 cm u0=1.25 cm;M∞= ? From f01=v01−u01 ⇒1.21=v01−(−1.25)1 ⇒v01=1.21−1.251⇒v0=30 cm Magnification at infinity, M∞=−u0v0×feD=1.2530×325(∵D=25 cm least distance of distinct vision) =200 Hence the magnifying power of the compound microscope is 200