Given: Separation of lens for two of its position, d=10 cm Ratio of size of the images in two positions I2I1=23 Distance of object from the screen, D= ? Applying formula, I2I1=(D−d)2(D+d)2⇒23=(D−10)2(D+10)2⇒23=D2+100−20DD2+100+20D⇒3D2+300−60D=2D2+200+40D⇒D2−100D+100=0 On solving, we get D=99 cm Hence the distance between the screen and the object is 99 cm.