Magnetic moment of the hydrogen atom, when the electron is in nth excited state, i.e., n′=(n+1) As magnetic moment Mn=InA=in(πrn2) $\begin{aligned}
& i_n=e V_n=\frac{m z^2 e^5}{4 \varepsilon_0^2 n^3 h^3} \
& r_n=\frac{n^2 h^2}{4 \pi^2 k z m e^2}\left(k=\frac{1}{4 \pi \epsilon_0}\right)
\end{aligned}Solvingwegetmagneticmomentofthehydrogenatomfor\mathrm{n}^{\text {th }}excitedstateM_{n^{\prime}}=\left(\frac{e}{2 m}\right) \frac{n h}{2 \pi}$
In the Bohr model an electron moves in a circular orbit around the proton. Considering the orbiting electron to be a circular current loop, the…
JEE Main 2013 — Physics Modern Physics
2013mcqhard
In the Bohr model an electron moves in a circular orbit around the proton. Considering the orbiting electron to be a circular current loop, the magnetic moment of the hydrogen atom, when the electron is in nth excited state, is :
Official previous-year question
Held on 9 Apr 2013 · Verified 6 Jul 2026.
Options
- A
(2me2πn2h)
- B
(me)2πnh
- C
(2me)2πnh
- D
(me)2πn2h
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