E=λhc⇒λ=Ehc=12.5×1.6×10−196.62×10−34×3×108=993 A∘λ1=R(n121−n221) (where Rydberg constant , R=1.097×107 ) or, 993×10−101=1.097×107(121−n221) Solving we get n2=3 Spectral lines Total number of spectral lines =3 Two lines in Lyman series for n1=1,n2=2 and n1=1,n2=3 and one in Balmer series for n1=2,n2=3 