Since the frequency of ultraviolet light is less than the frequency of X-rays, the energy of each incident photon will be more for X-rays K.Ephotoelectron=hv−φ Stopping potential is to stop the fastest photoelectron V0= so, KEEmax and V0 both increases. But K.E ranges from zero to K.E Emax because of loss of energy due to subsequent collisions before getting ejected and not due to range of frequencies in the incident light.
Statement-1 : When ultraviolet light is incident on a photocell, its stopping potential is V_0 and the maximum kinetic energy of the photoelectrons…
JEE Main 2010 — Physics Modern Physics
2010mcqeasy
Statement-1 : When ultraviolet light is incident on a photocell, its stopping potential is V0 and the maximum kinetic energy of the photoelectrons is Kmax. When the ultraviolet light is replaced by X− rays, both V0 and Kmax increase. Statement-2 : Photoelectrons are emitted with speeds ranging from zero to a maximum value because of the range of frequencies present in the incident light. Of the four choices given after the statements, choose the one that best describes the two statements.
Official previous-year question
Held on 30 Apr 2010 · Verified 6 Jul 2026.
Options
- A
Statement-1 is true, Statement-2 is true; Statement-2 is the correct explanation of Statement-1.
- B
Statement-1 is true, Statement-2 is true; Statement-2 is not the correct explanation of Statement- 1.
- C
Statement-1 is false, Statement-2 is true.
- D
Statement-1 is true, Statement- 2 is false.
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