Since the frequency of ultraviolet light is less than the frequency of X-rays, the energy of each incident photon will be more for X-rays K.Ephotoelectron=hv−φ Stopping potential is to stop the fastest photoelectron V0= so, KEEmax and V0 both increases. But K.E ranges from zero to K.E Emax because of loss of energy due to subsequent collisions before getting ejected and not due to range of frequencies in the incident light.