Energy released = total binding energy of product − total binding energy of reactants ⇒28−(2×2.2)=28−4.4=236MeV
The binding energy per nucleon of deuteron ( _1^2 H ) and helium nucleus ( _2^4 He ) is 1.1 MeV and 7 MeV respectively. If two deuteron nuclei react…
JEE Main 2004 — Physics Modern Physics
The binding energy per nucleon of deuteron (12H) and helium nucleus (24He) is 1.1MeV and 7MeV respectively. If two deuteron nuclei react to form a single helium nucleus, then the energy released is
Held on 30 Apr 2004 · Verified 6 Jul 2026.
Options
- A
13.9MeV
- B
26.9MeV
- C
23.6MeV
- D
19.2MeV
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