Let the distance of point x from the origin O be r.
Point x lies on the axial line of dipole A. The electric field at x due to dipole A is directed along the horizontal axis and its magnitude is given by:
EA=4πϵ01r32p1
Point x lies on the equatorial line of dipole B. The electric field at x due to dipole B is directed perpendicular to the horizontal axis and its magnitude is given by:
EB=4πϵ01r3p2
The resultant electric field makes an angle of 60∘ with the line Ox (the horizontal axis). Therefore, the tangent of this angle is the ratio of the perpendicular component of the electric field to the parallel component:
tan60∘=EAEB
Substituting the expressions for EA and EB:
3=4πϵ01r32p14πϵ01r3p2
3=2p1p2
p1p2=23
Answer: 23
