The four parallel branches between the common left node A and the common right node are all identical: each consists of a 27 V source in series with a 3 Ω resistor. In the third branch, the two cells (14 V and 13 V) aid each other, giving a net EMF of 14+13=27 V.
Thevenin equivalent between A and B:
Since all four branches have the same EMF and polarity in parallel:
Vth=27 V
The four 3 Ω resistors in parallel give:
Rth=43=0.75 Ω
Load branch (diagonal):
The diagonal connecting A and B consists of two 3 Ω resistors in series, so:
RL=3+3=6 Ω
Current through the diagonal branch:
I=Rth+RLVth=0.75+627=6.7527=4 A
Voltage across A and B:
VAB=I⋅RL=4×6=24 V
Hence, the voltage is 24 V and the current is 4 A, which corresponds to option (2) 24 V, 4 A.
