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Match List - I with List - II. … Choose the correct answer from the options given below :

JEE Main 2026 — Physics Electromagnetism

2026mcqeasy

Match List - I with List - II.

List - IList - IIRelationLawA. ∮E⃗⋅dl→=−ddt∮B⃗⋅da→I. Ampere’s circuital lawB. ∮B⃗⋅dl→=μ0(I+ϵ0dϕEdt)II. Faraday’s laws ofelectromagnetic inductionC. ∮E⃗⋅da→=1ϵ0∫VρdvIII. Ampere - Maxwell lawD. ∮B⃗⋅dl→=μ0IIV. Gauss’s law of electrostatics\begin{array}{l} \text{List - I} & \text{List - II} \\ \text{Relation} & \text{Law} \\ \text{A. } \oint \vec{E} \cdot \overrightarrow{d l}=-\frac{d}{d t} \oint \vec{B} \cdot \overrightarrow{d a} & \text{I. Ampere's circuital law} \\ \text{B. } \oint \vec{B} \cdot \overrightarrow{d l}=\mu_{0}\left(I+\epsilon_{0} \frac{d \phi_{E}}{d t}\right) & \text{II. Faraday's laws of} \\ & \text{electromagnetic induction} \\ \text{C. } \oint \vec{E} \cdot \overrightarrow{d a}=\frac{1}{\epsilon_{0}} \int_{\mathrm{V}} \rho \mathrm{dv} & \text{III. Ampere - Maxwell law} \\ \text{D. } \oint \vec{B} \cdot \overrightarrow{d l}=\mu_{0} I & \text{IV. Gauss's law of electrostatics} \end{array}List - IRelationA. ∮E⋅dl=−dtd​∮B⋅daB. ∮B⋅dl=μ0​(I+ϵ0​dtdϕE​​)C. ∮E⋅da=ϵ0​1​∫V​ρdvD. ∮B⋅dl=μ0​I​List - IILawI. Ampere’s circuital lawII. Faraday’s laws ofelectromagnetic inductionIII. Ampere - Maxwell lawIV. Gauss’s law of electrostatics​

Choose the correct answer from the options given below :

Official previous-year question

Held on 23 Jan 2026 · Verified 6 Jul 2026.

Options

  1. A

    A-II, B-III, C-I, D-IV

  2. B

    A-II, B-III, C-IV, D-I

  3. C

    A-I, B-IV, C-III, D-II

  4. D

    A-IV, B-I, C-II, D-III

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