Given V=10 V and I=5 A
Least count of voltmeter, ΔV=500 mV=0.5 V
Least count of ammeter, ΔI=200 mA=0.2 A
Resistance is given by Ohm's law:
R=IV=510=2 Ω
The maximum permissible relative error in resistance is:
RΔR=VΔV+IΔI
2ΔR=100.5+50.2
2ΔR=0.05+0.04=0.09
ΔR=2×0.09=0.18 Ω
Answer: 0.18