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Consider two identical metallic spheres of radius R each having charge Q and mass m. Their centers have an initial separation of 4 R. Both the…

JEE Main 2026 — Physics Electromagnetism

2026mcqmedium

Consider two identical metallic spheres of radius RRR each having charge QQQ and mass mmm. Their centers have an initial separation of 4R4 R4R. Both the spheres are given an initial speed of uuu towards each other. The minimum value of uuu, so that they can just touch each other is :

(Take k=14πϵ0k=\frac{1}{4 \pi \epsilon_{0}}k=4πϵ0​1​ and assume kQ2>Gm2k Q^{2}>G m^{2}kQ2>Gm2 where GGG is the Gravitational constant)

Official previous-year question

Held on 21 Jan 2026 · Verified 6 Jul 2026.

Options

  1. A

    kQ22mR(1−Gm2kQ2)\sqrt{\frac{k Q^{2}}{2 m R}\left(1-\frac{G m^{2}}{k Q^{2}}\right)}2mRkQ2​(1−kQ2Gm2​)​

  2. B

    kQ24mR(1−Gm2kQ2)\sqrt{\frac{k Q^{2}}{4 m R}\left(1-\frac{G m^{2}}{k Q^{2}}\right)}4mRkQ2​(1−kQ2Gm2​)​

  3. C

    kQ22mR(1−Gm22kQ2)\sqrt{\frac{k Q^{2}}{2 m R}\left(1-\frac{G m^{2}}{2 k Q^{2}}\right)}2mRkQ2​(1−2kQ2Gm2​)​

  4. D

    kQ24mR(1+Gm2kQ2)\sqrt{\frac{k Q^{2}}{4 m R}\left(1+\frac{G m^{2}}{k Q^{2}}\right)}4mRkQ2​(1+kQ2Gm2​)​

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